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CBSE Class 12 Math 2020 Delhi Set 2 Solved Paper

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Question : 5
Total: 11
Evaluate : sin‌[‌
π
3
−sin‌−1(‌
−1
2
)]
Solution:  
The value of sin‌(‌
π
3
−sin‌−1(−‌
1
2
))
=sin‌(‌
π
3
−(−‌
π
6
))
=sin‌‌
π
2

=1
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