CBSE Class 12 Math 2020 Outside Delhi Set 1 Solved Paper

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Question : 20
Total: 36
Show that the function y=ax+2a2 is a solution of the differential equation 2(
dy
dx
)
2
+x(
dy
dx
)
y
=0
The given function is
y=ax+2a2(i)
Differentiating equation (i) w.r.t. ' x ', we get dydx=a
Substituting the value of 'a' in equation, we get
y=x(
dy
dx
)
+2(
dy
dx
)
2

2(
dy
dx
)
2
+x(
dy
dx
)
y
=0
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