If x=2 \cos \theta-\cos 2 \theta and y=2 \sin \theta- \sin ...

CBSE Class 12 Math 2022 Term I Solved Paper

Question : 22 of 50

Marks: +1, -0

x=2 \cos θ-\cos 2 θ

and

y=2 sin \;θ- sin \;2 θ

, then

\;{d y}/{d x}

Solution: 👈: Video Solution

\;\text " Explanation: Given, "\;\;x=2 \cos θ-\cos 2 θ

\;\text " and "\;\;y\;=2 sin \;θ- sin \;2 θ

\;\;\text " Therefore, "\;\;\;{d x}/{d θ}\;=-2 sin \;θ+2 sin \;2 θ

\;\text " and "\;\;\;{d y}/{d θ}\;=2 \cos θ-2 \cos 2 θ

∴ \;\;{d y}/{d x}\;=\;{2 \cos θ-2 \cos 2 θ}/{-2 sin \;θ+2 sin \;2 θ}

\;\;\text " or "\;\;\;{d y}/{d x}\;=\;{\cos θ-\cos 2 θ}/{ sin \;2 θ- sin \;θ}

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