CBSE Class 12 Math 2022 Term I Solved Paper

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Question : 15
Total: 50
If R={(x,y);x,yZ,x2+y24} is a relation in set Z, then domain of R is
Explanation: Given,
R={(x,y):x,yZ,x2+y24}
Since, beginalignedy=f(x)
y=4x2endaligned
For, x=0,±1,±2,y=±2,±3,0
Since,
Hence, the required domain will be 0±1,±2
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