CBSE Class 12 Math 2022 Term I Solved Paper

Question : 3

Total: 50

A function f:R→R is defined as f(x)=x3+1. Then the function has

no minimum value
no maximum value
both maximum and minimum values
neither maximum value nor minimum value

Solution: 👈: Video Solution

Explanation: Given, f(x)=x3+1
∴‌f′(x)‌=3x2‌ and ‌f′′(x)=6x
‌ Put ‌‌f′(x)‌=0
⇒3x2‌=0⇒x=0
‌‌ At ‌‌x‌=0,f′′(x)=0
Thus, f(x) has neither maximum value nor minimum value.

Go to Question:

Prev Question

Next Question