CBSE Class 12 Math 2022 Term I Solved Paper

Question : 42

Total: 50

The corner points of the feasible region determined by a set of constraints (linear inequalities) are P(0,5), Q(3,5),R(5,0) and S(4,1) and the objective function is Z=ax+2by where a,b>0. The condition on a and b such that the maximum Z occurs at Q and S is

a−5b=0
a−3b=0
a−2b=0
a−8b=0

Solution: 👈: Video Solution

Explanation: Given, Max. Z=ax+2by
Max. value of Z on Q(3,5)= Max. value of Z on S(4,1)
⇒‌3a+10b‌=4a+2b
⇒‌a−8b‌=0

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