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CBSE Class 12 Math 2023 Delhi Set 2 Solved Paper

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Question : 4
Total: 14
The value of
π∕4
∫
0
(sin‌2x)‌dx is:
Solution:  
Explanation:
π∕4
∫
0
sin‌2x‌dx
Let ‌‌u=2x
If x=0 then, u=0
‌ and ‌x=π∕4‌ then ‌u=π∕2‌. ‌
⇒‌‌du=2‌dx
‌
1
2
‌
π∕2
∫
0
sin‌u‌du=−‌
1
2
[cos‌u]0π∕2
=−‌
1
2
[0−1]=‌
1
2

‌
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