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CBSE Class 12 Physics 2013 Paper

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Question : 1
Total: 29
Write the expression for the work done on an electric dipole of dipole moment
→
p
 in turning it from its position of stable equilibrium to a position of unstable equilibrium in a uniform electric field
→
E
.
Solution:  
In stable equilibrium the angle between
→
P
 and
→
E
 is 0∘
In unstable equilibrium the angle between
→
P
 and
→
E
 is 180∘
‌ So, ‌‌‌ ‌ the work done ‌‌=PE(cos‌θ1−cos‌θ2)
=PE(cos‌0∘−cos‌180∘)
‌=PE(1+1)
‌=2PE
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