CBSE Class 12 Physics 2013 Paper

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Question : 19
Total: 29
(a) When an a.c. source is connected to an ideal capacitor show that the average power supplied by the source over a complete cycle is zero.
(b) A lamp is connected in series with a capacitor. Predict your observations when the system is connected first across a d.c. and then an a.c. source. What happens in each case if the capacitance of the capacitor is reduced?
Solution:  
(a) AC source connected to a ideal capacitor:
Using KVL,
V0sinωt=
q
C

Or, q=CV0sinωt
Or, I=
dq
dt
=CV0ωcosωt

I=I0cosωt=I0sin(ωt+
π
2
)

Average Power =
1
T
T
0
[V0sinωt×I0sin(ωt+
π
2
)
]
dt

=
1
T
T
0
[
1
2
V0
I0
s
i
n
2ωt
]
dt

=0
(b) Reactance of a capacitor =XC=
1
2
π
f
C

For DC, f=0,XC=, No current flow, bulb does not glow.
For AC,f0,XC, current flows, bulb glows.
Capacitance is reduced.
For DC, f=0,XC=, No current flow, bulb does not glow.
For AC, as C reduces, XC increases, current decreases, bulb glows less bright.
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