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Question : 24
Total: 30
Obtain the expression for the energy stored per unit volume in a charged parallel plate capacitor.
(b) The electric field inside a parallel plate capacitor isE . Find the amount of work done in moving a charge q over a closed rectangular loop abcda.
OR
(a) Derive the expression for the capacitance of a parallel plate capacitor having plate areaA and plate separation d .
(b) Two charged spherical conductors of radiiR 1 and R 2 when connected by a conducting wire acquire charge q 1 and q 2 respectively. Find the ratio of their surface charge densities in terms of their radii.
(b) The electric field inside a parallel plate capacitor is
OR
(a) Derive the expression for the capacitance of a parallel plate capacitor having plate area
(b) Two charged spherical conductors of radii
Solution:
(b) W = Force × Displacement
F = q E
As displacement= 0 , so work done is also zero.
(a)
E =
=
∴ V = E d =
Capacitance, C =
=
(b) When the two charged spherical conductors are connected by a conducting wire they acquire the same potential.
i.e.,
=
⇒
=
Hence, ratio of surface charge densities,
=
=
=
×
=
As displacement
(a)
(b) When the two charged spherical conductors are connected by a conducting wire they acquire the same potential.
i.e.,
Hence, ratio of surface charge densities,
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