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Question : 5
Total: 8
Given a uniform electric field
= 2 × 10 3
N ∕ C . Find the flux of this field through a square of side 20 cm , whose plane is parallel to the Y − Z plane. What would be the flux through the same square, if the plane makes an angle of 30 ∘ with the X -axis?
Solution:
(a) The plane of the square is parallel to the y − z plane. Hence, angle between the unit vector normal to the plane and electric field, θ = 0 ∘
Flux (ϕ) through the plane is given by the relation,
ϕ = |
| A cos θ
= 2 × 10 3 × 0.04 × cos 0 ∘
= 80 N m 2 ∕ C
(b) Plane makes an angle of30 ∘ with the x -axis. Hence, angle between the unit vector normal to the plane and electric field, θ = 60 ∘
Flux,ϕ = |
| A cos θ
= 2 × 10 3 × 0.04 × cos 60 ∘
= 40 N m 2 ∕ C
Flux (ϕ) through the plane is given by the relation,
(b) Plane makes an angle of
Flux,
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