CBSE Class 12 Physics 2014 Delhi Set 2 Paper

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Question : 5
Total: 8
Given a uniform electric field
E
=2×103
^
i
N
C
. Find the flux of this field through a square of side 20cm, whose plane is parallel to the YZ plane. What would be the flux through the same square, if the plane makes an angle of 30 with the X-axis?
Solution:  
(a) The plane of the square is parallel to the yz plane. Hence, angle between the unit vector normal to the plane and electric field, θ=0
Flux (ϕ) through the plane is given by the relation,
ϕ=|
E
|Acosθ

=2×103×0.04×cos0
=80Nm2C
(b) Plane makes an angle of 30 with the x-axis. Hence, angle between the unit vector normal to the plane and electric field, θ=60
Flux, ϕ=|
E
|Acosθ

=2×103×0.04×cos60
=40Nm2C
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