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Question : 6
Total: 8
A 12.9 eV beam of electronic is used to bombard gaseous hydrogen at room temperature.
Upto which energy level the hydrogen atoms would be excited? Calculate the wavelength of the first member of Paschen series and first member of Balmer series.
Upto which energy level the hydrogen atoms would be excited? Calculate the wavelength of the first member of Paschen series and first member of Balmer series.
Solution:
Energy of the electron in the n th state of an atom Here, Z is the atomic number of the atom.
For hydrogen atom,Z = 1
Energy required to excite an atom from initial state( n i ) to final state ( n f ) ,
E = − 13.6 (
−
) eV
⇒
+
= 12.9
This energy must be equal to or less than the energy of the incident electron beam.
⇒ 13.6 − 12.9 =
[ ∵ n ′ = 1 ]
⇒ n f = 4.4
State cannot be a fraction number.
⇒ n f = 4
Hence, the hydrogen atom would be excited up to4 th energy level.
Rydberg's formula for the spectrum of the hydrogen atom is given by:
= R (
−
)
Here,λ is the wavelength
Rydberg's canstant,R = 1.097 × 10 7 m − 1
For the first member of the Paschen series
= 1.097 × 10 7 (
−
)
λ = 18752.4 Å
For the first member of Balmer series
n 1 = 2 , n 2 = 3
= 1.097 × 10 7 (
−
)
λ = 6563.3 Å
For hydrogen atom,
Energy required to excite an atom from initial state
This energy must be equal to or less than the energy of the incident electron beam.
State cannot be a fraction number.
Hence, the hydrogen atom would be excited up to
Rydberg's formula for the spectrum of the hydrogen atom is given by:
Here,
Rydberg's canstant,
For the first member of the Paschen series
For the first member of Balmer series
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