CBSE Class 12 Physics 2014 Outside Delhi Set 1 Paper

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Question : 22
Total: 30
A convex lens of focal length 20‌cm is placed coaxially with a convex mirror of radius of curvature 20‌cm. The two are kept at 15‌cm apart from each other. A point object lies 60‌cm in front of the convex lens. Draw a ray diagram to show the formation of the image by the combination. Determine the nature and position of the image formed.
Solution:  
u=−60‌cm‌ and ‌f=20‌cm
From the lens formula, we have:


‌
1
v
−‌
1
u
‌
=‌
1
f

‌
1
v
‌
=‌
1
f
+‌
1
u

‌=‌
1
20
+‌
1
−60

‌=‌
3−1
60
=‌
2
60
=‌
1
30

v‌=+30‌cm
The positive sign indicates that the image is formed at the right of the lens.


The image I1 is formed behind the mirror and acts as a virtual oject for the mirror. The convex mirror forms the image I2, whose distance from the mirror can be determined as:

‌
1
v
+‌
1
u
‌
=‌
1
f

Here, u‌=15‌cm
and, f‌=‌
R
2
=10‌cm

‌
1
v
‌
=‌
1
f
−‌
1
u

v‌=30‌cm
Hence, the final virtual image is formed at a distance 30‌cm from the convex mirror.
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