CBSE Class 12 Physics 2014 Outside Delhi Set 1 Paper

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Question : 28
Total: 30
Draw a labelled diagram of Van de Graff generator. State its working principle to show how by introducing a small charged sphere into larger sphere, large amount of charge can be transferred to the outer sphere. State the use of this machine and also point out its limitations.
OR
(a) Deduce the expression for the torque acting on a dipole of dipole moment
p
in the presence of a uniform electric field
E
.
(b) Consider two hollow concentric spheres, S1 and S2, enclosing charges 2Q and 4Q respectively as shown in the figure.
(i) Find out the ratio of the electric flux through them.
(ii) how will the electric flux through the sphere S1 change if a medium of dielectric constant ' εr ', ' εr ', is introduced in the space inside S1 in place of air?
Deduce the necessary expression.
Solution:  
OR
(a) Consider an electric dipole consisting of charges q and +q and of length 2a placed in a uniform electric field
E
making an angle θ with electric field.
Force on charge q at A=q
E
(opposite to
E
)
Force on charge +q at B=+q
E
(
along
E
)

Electric dipole is under the action of two equal and unlike parallel force, which give rise to a torque on the dipole.
τ= Force × Perpendicular distance between the two forces
τ=qE(AN)=qE(2asinθ)
τ=pEsinθ [2qa=P]
τ
=
p
×
E

(b) (i) Charge enclosed by sphere S1=2Q
By Gauss' law, electric flux through sphere S1 is
ϕ1=
2Q
ε0

Charge enclosed by sphere S2 is
Q=2Q+4Q=6Q
Electric flux through sphere S2 is
ϕ2=
6Q
ε0

The ratio of the electric flux is
ϕ1
ϕ2
=
2Q
ε0
6Q
ε0
=
2
6
=
1
3

(ii) For sphere S1, the electric flux is
ϕ=
2Q
εr

ϕ
ϕ1
=
ε0
εr

ϕ=ϕ1×
ε0
εr

εr>ε0
ϕ<ϕ1
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