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CBSE Class 12 Physics 2014 Outside Delhi Set 1 Paper

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Question : 3
Total: 30
What is the force between two small charges of 2×10−7C and 3×10−7C placed 30‌cm apart in air?
Solution:  
F‌=‌
kq1q2
r2
‌=‌
9×109×2×10−7×3×10−7
(30×10−2)2
‌=6×10−3N
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