CBSE Class 12 Physics 2014 Outside Delhi Set 3 Paper

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Question : 7
Total: 9
A convex lens of focal length 20‌cm is placed coaxially with a convex mirror of radius of curvature 20‌cm. The two are kept at 15‌cm from each other. A point object placed 40‌cm in front of the convex lens. Find the position of the image formed by this combination. Draw a ray diagram to show the formation.
Solution:  
Given, A=−40‌cm and, f=20‌cm
From the lens formula, we have:
‌
1
v
−‌
1
u
‌
=‌
1
f

⇒‌
1
v
‌
=‌
1
f
+‌
1
u

⇒‌
1
v
‌
=‌
1
20
+‌
1
(−40)

⇒‌
1
v
‌
=‌
2−1
40
=‌
1
40

‌v‌=40‌cm
The positive sign describes that the image is formed to the right of the lens.

The image I1 is formed behind the mirror and thus acts as a virtual source for the mirror. The convex mirror forms the image I2, whose distance from the mirror is given by:
‌
1
v
+‌
1
v
=‌
1
f

Here: ‌u=25‌cm
‌f=‌
R
2
=10‌cm

‌
1
v
+‌
1
v
‌
=‌
1
f

⇒‌‌‌
1
v
‌
=‌
1
f
−‌
1
u

⇒‌
1
v
=‌
1
10
−‌
1
25

⇒‌
1
v
=‌
5−2
50
=‌
3
50

⇒v=+16.67‌cm
Hence, the final image is formed at a distance of 16.67‌cm behind the convex mirror.
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