CBSE Class 12 Physics 2015 Delhi Set 1 Paper

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Question : 12
Total: 26
(i) A giant refracting telescope has an objective lens of focal length 15m. If an eye piece of focal length 1.0cm is used, what is the angular magnification of the telescope?
(ii) If this telescope is used to view the moon, what is the diameter of the image of the moon formed by the objective lens ? The diameter of the moon is 3.48×106m and the radius of lunar orbit is 3.8× 108m.
Solution:  
(i) Calculation of angular magnification
(ii) Calculation of image of diameter of Moon
Angular Magnification
m=
fo
fe

=
15
102
=1500

Angular size of the moon =(
3.48×106
3.8×108
)

=
3.48
3.8
×102
radian

Angular size of the image
=(
3.48
3.8
×102
×1500
)
radian

Diameter of the image
=
3.48
3.8
×15
×
focal length of eye peice

=
3.48
3.8
×15
×1cm

=13.7cm
(Also accept alternative correct method.)
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