CBSE Class 12 Physics 2017 Delhi Set 1 Paper

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Question : 20
Total: 26
(i) A ray of light incident on face AB of an equilateral glass prism, shows minimum deviation of 30∘. Calculate the speed of light through the prism.

(ii) Find the angle of incidence at face AB so that the emergent ray grazes along the face AC.
Solution:  
(i) Calculation of speed of light
(ii) Calculation of angle of incidence at face AB
(i) µ=‌
sin‌(
A+δm
2
)
sin‌(‌
A
2
)

‌=‌
sin‌(
60∘+30∘
2
)
sin‌(‌
60∘
2
)
=√2

‌ Also ‌‌‌µ‌=‌
c
v
⇒v
=‌
3×108
√2
m
∕ s

v‌=2.122×108m∕ s
(ii)

At face AC, let the angle of incidence be r2.
For grazing ray, e=90∘
⇒‌‌µ=‌
1
sin‌r2
⇒r2
=sin‌−1(‌
1
√2
)
=45∘

Let angle of refraction at face AB be r1.
Now r1+r2=A
∴‌‌r1=A−r2=60∘−45∘=15∘
Let angle of incidence at this face be i
‌µ‌=‌
sin‌i
sin‌r1

⇒‌‌µ‌=√2=‌
sin‌i
sin‌15∘

∴‌i‌=sin‌−1(√2⋅sin‌15∘)
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