(i) Calculation of equivalent capacitance
(ii) Calculation of charge and energy stored
(i) Capacitors C2,C3 and C4 are in parallel
∴‌C234=C2+C3+C4
∴‌C234=6µF
Capacitors C1,C234 and C5 are in series
‌

1

Ceq

=‌

1

C1

+‌

1

C234

+‌

1

C5

=‌

1

2

+‌

1

6

+‌

1

2

‌=‌

7

6

µF
Ceq‌=‌

6

7

µF
(ii) Charge drawn from the source
Q‌=CeqV,
‌=‌

6

7

×7µC=6µC
Energy stored
U‌=‌

Q2

2C

‌=‌

6×6×10−12×7

2×6×10−6

=21µJ