CBSE Class 12 Physics 2017 Delhi Set 2 Paper

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Question : 7
Total: 8
A electron of mass me revolves around a nucleus of charge +Ze. Show that it behaves like a tiny magnetic dipole. Hence prove that the magnetic moment associated with it is expressed as
→
µ
=‌
e
2me
→
L
, where
→
L
is the orbital angular momentum of the electron. Give the significance of negative sign.
Solution:  
(i) Behaviour of revolving electron as a tiny magnetic dipole
(ii) Proof of the relation
→
µ
=−‌
e
2me
→
L

(iii) Significance of negative sign
Electron, in circular motion around the nucleus, constitutes a current loop which behaves like a magnetic dipole.
Current associated with the revolving electron :

‌I=‌
e
T

‌ and ‌‌‌T‌=‌
2Ï€r
v

∴‌‌I=‌
e
2Ï€r
v


Magnetic moment of the loop, µ=IA
µ=LA=‌
ev
2Ï€r
Ï€
r2
=‌
evr
2
=‌
eâ‹…mevr
2me

Orbital angular momentum of the electron
L‌=mevr
→
µ
‌
=‌
−e
2me
→
L

-ve sign signifies that the angular momentum of the revolving electron is opposite in direction to the magnetic moment associated with it.
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