CBSE Class 12 Physics 2017 Outside Delhi Set 2 Paper

Question : 9

Total: 9

Two identical loops P and Q each of radius 5‌cm are lying in perpendicular planes such that they have a common centre as shown in the figure. Find the magnitude and direction of the net magnetic field at the common centre of the two coils, if they carry currents equal to 3A and 4A respectively.

Solution:

Formula
Field due to each coil
Magnitude of resultant field
Direction of resultant field
Field at the centre of a circular coil =‌

µ0I

Field due to coil P=‌

µ0×3

2×5×10−2

tesla
=12π×10−6‌ tesla ‌
Field due to coil Q=‌

µ0×3

2×5×10−2

tesla
=16π×10−6‌ tesla ‌
∴ Resultant Field =(π√122+162)µT
=(20π)µT
Let the field make an angle θ with the vertical
‌tan‌θ=‌

12π×10−6

16π×10−6

=‌

‌θ=tan−1‌

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