CBSE Class 12 Physics 2018 Delhi Set 1 Paper

© examsnet.com
Question : 16
Total: 26
(a) If one of two identical slits producing interference in Young's experiment is covered with glass, so that the light intensity passing through it is reduced to 50%, find the ratio of the maximum and minimum intensity of the fringe in the interference pattern.
(b) What kind of fringes do you expect to observe if white light is used instead of monochromatic light?
Solution:  
(a) Finding the (modified) ratio of the maximum and minimum intensities
(b) Fringes obtained with white light
(a) After the introduction of the glass sheet (say, on the second slit),
we have
I2
I1
=50%
=
1
2

Ratio of the amplitudes
=
a2
a1
=
1
2
=
1
2

Hence
Imax
Imin
=(
a1+a2
a1a2
)
2

=(
1+
1
2
1
1
2
)
2
=(
2+1
21
)
2

(34)
(b) The central fringe remains white.
No clear fringe pattern is seen after a few (coloured) fringes on either side of the central fringe.
[Note : For part (a) of this question, The student may
(i) Just draw the diagram for the Young's double slit experiment.
Or
(ii) Just state that the introduction of the glass sheet would introduce an additional phase difference and the position of the central fringe would shift.
© examsnet.com
Go to Question: