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Question : 19
Total: 26
(a) Explain the processes of nuclear fission and nuclear fusion by using the plot of binding energy per nucleon ( B E ∕ A ) versus the mass number A .
(b) A radioactive isotope has a half-life of1 0 years. How long will it take for the activity to reduce to 3.125 % ?
(b) A radioactive isotope has a half-life of
Solution:
(a) Plot of binding energy per nucleon is shown in Figure. From BE/nucleon curve, we note that first B.E. increases rapidly and then decreases slowly and B.E is max i.e. 8.8 Mev for 56 Fe atom. Again by decreasing slowly B.E. become 8.5Mev for uranium atom 92 238 U . This shows that nucleus with mass number A < 20 are less stable, but some nucleus as 4 He , 12 C , 16 O (even-even) nuclei are stable. Thus the nuclei with mass number A < 20 shows fusion reaction as 2 H and 3 H have very low BE ∕ nucleon in comparison to 4 He . Thus when two very light nuclei ( A ≤ 10 say) fuse to form a heavy nucleus, the B.E/A of fused heavier nucleus is more than the B.E/A of lighter nuclei. This implies release of energy in nuclear fusion.
Similarly, due to fission of a very heavy nucleus, the B.E/A of the product as daughter nuclei increases which implies the release of huge amount of energy.
Thus for lighter nuclei nuclear fusion and for heavier nuclei nuclear fission takes place and huge amount of energy is released.
(b) Let the initial activity isR 0 and final activity is R then we have
= (
) t ∕ T 1 ∕ 2
GivenR = 3.125 % ,
R =
R o , T
= 10 years.
R = 0.03125 R 0
⇒
= 0.03125 = (
) 5
⇒ (
) 5 = (
) t ∕ 1 ∕ 1 ∕ 2
⇒
= 5 or t = 5 T
t = 5 × 10
t = 50 years
Similarly, due to fission of a very heavy nucleus, the B.E/A of the product as daughter nuclei increases which implies the release of huge amount of energy.
Thus for lighter nuclei nuclear fusion and for heavier nuclei nuclear fission takes place and huge amount of energy is released.
(b) Let the initial activity is
Given
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