CBSE Class 12 Physics 2019 Delhi Set 1 Paper

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Question : 15
Total: 27
(a) Identify the part of electromagnetic spectrum used in (i) radar and (ii) eye surgery. Write their frequency range.
(b) Prove that the average energy density of the oscillating electric field is equal to that of the oscillating magnetic field.
Solution:  
(a) Identification
Frequency range
(b) Proof
Microwaves: Frequency range
(∼1010‌ to ‌1012‌Hz)
Ultraviolet rays: Frequency range
(∼1015‌ to ‌1017‌Hz)
(b) Average energy density of the electric field
‌=‌
1
2
ε0
E2

‌=‌
1
2
ε0
(cB)2

‌=‌
1
2
ε0
‌
1
µ0ε0
B2

‌=‌
1
2
‌
B2
µ0

= Average energy density of the magnetic field.
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