CBSE Class 12 Physics 2019 Delhi Set 1 Paper

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Question : 19
Total: 27
Draw a labelled ray diagram of an astronomical telescope in the near point adjustment position. A giant refraction telescope at an observatory has an objective lens of focal length 15m and an eyepiece of focal length 1.0cm. If this telescope is used to view the moon, find the diameter of the image of the moon formed by the objective lens. The diameter of the moon is 3.48×106m, and the radius of lunar orbit is 3.8×108m.
Solution:  
Magnifying power of telescope, m=
fo
fe

here fo=15m,fe=1.0cm=0.01m
m=
15
0.01
=1500.

Let D be diameter of moon, d be diameter of image of moon formed by objective and r the distance of moon from objective lens then from figure,
D
r
=
d
fo

d=
D
r
fo

=
3.48×106
3.8×108
×15m

=0.137m=13.7cm.
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