CBSE Class 12 Physics 2019 Outside Delhi Set 1 Paper

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Question : 17
Total: 27
Two large charged plane sheets of charge densities σ and 2σCm2 are arranged vertically with a separation of d between them. Deduce expressions for the electric field at points
(i) to the left of the first sheet, (ii) to the right of the second sheet, and (iii) between the two sheets.
OR
A spherical conducting shell of inner radius r1 and outer radius r2 has a charge Q.
(a) A charge q is placed at the centre of the shell. Find out the surface charge density on the inner and outer surfaces of the shell.
(b) Is the electric field inside a cavity (with no charge) zero-independent of the fact whether the shell is spherical or not? Explain.
Solution:  
Diagram
Deducing electric field expression
(i) To the left of first sheet
(ii) To the right of second sheet
(iii) Between the two sheets
Diagram :

Electric field in the region left of first sheet
EI=E1+E2
EI=
σ
ε0
σ
2ε0

EI=+
σ
2ε0

It is towards right,
Electric field in the region to the right of second sheet
EII=
σ
2ε0
σ
ε0

EII=
σ
2ε0

It is towards left,
Electric field between the two sheets
EIII =EI+EII
EIII =
σ
ε0
+
σ
2ε0

EIII =
3σ
2ε0

Electric field is towards the right.
OR
Diagram
Finding the surface charge density in the inner and outer surface of the shell
Electric field in the cavity
Diagram:

The surface charge density on inner surface of the shell is σ1=
q
4πr12

The surface charge density on outer shell is
σ2=
Q+q
4πr22

(b) Consider a Gaussian surface inside the shell, net flux is zero since qnet =0. According to Gauss's law it is independent of shape and size of shell.
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