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Question : 34
Total: 37
When a conducting loop of resistance 10 Ω 10 cm 2
Find the -
(a) total charges passed through the loop.
(b) change in magnetic flux through the loop.
(c) magnitude of the magnetic field applied.
Find the -
(a) total charges passed through the loop.
(b) change in magnetic flux through the loop.
(c) magnitude of the magnetic field applied.
Solution:
Given,
Area = A = 10 cm 2 =
m 2
Resistance= R = 10 Ω
From the graph, change in current= 0.4 A
Change in time= 1.0 s
(i) Total charge passed through the loop
= current × time = 0.4 × 1.0 = 0.4 C
(ii)| e | =
Or,i R =
Or,0.4 × 10 =
∴ = ∆ ϕ = 4 Wb
(iii)| e | = A
Or, i R = A
Or, 0.4 × 10 =
∴ ∆ B = 4000 T
Resistance
From the graph, change in current
Change in time
(i) Total charge passed through the loop
(ii)
Or,
Or,
(iii)
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