CBSE Class 12 Physics 2020 Outside Delhi Set 1 Paper

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Question : 33
Total: 37
Two coherent light waves of intensity 5× 102Wm2 each superimpose and produce the interference pattern on a screen. At a point where the path difference between the waves is
λ
6
,λ
being wavelength of the wave, find the
(a) phase difference between the waves
(b) resultant intensity at the point
(c) resultant intensity in terms of the intensity at the maximum
Solution:  
(a) x=
λϕ
2π
, where x= Path difference and
ϕ= Phase difference
x=
λ
6

ϕ= phase difference =
λ
6
×
2π
λ
=
2π
6

(b) Resultant intensity =I=I0cos2
ϕ
2

Or, I=I0cos2
π
6

Or, I=5×102cos2
π
6

Or, I=5×102(
3
2
)
2

I=3.75×102Wm2
(c) Resultant intensity at maxima =Imax=4I0
Resultant intensity =IRESULTANT =
3l0
4

(c) Resultant intensity at maxima =Imax=4I0
Resultant intensity =IRESULTANT =
3I0
4

IRESULTANT
IMAX
=
3I04
4I0
=
3
16

IRESULTANT =
3
16
IMAX
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