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Question : 2
Total: 4
An electron in a hydrogen atom makes transitions from orbits of higher energies to orbits of lower energies. 3
(i) When will such transitions result in (a) Lyman (b) Balmer series?
(ii) Find the ratio of the longest wavelength in Lyman series to the shortest wavelength in Balmer series.
(i) When will such transitions result in (a) Lyman (b) Balmer series?
(ii) Find the ratio of the longest wavelength in Lyman series to the shortest wavelength in Balmer series.
Solution:
(i) Emission spectrum of Hydrogen atom: Lyman and Balmer series:
Lyman Series: When electrons will jump from higher energy orbit ton = 1 orbit.
Balmer Series: When electrons will jump from higher energy orbit ton = 2 orbit.
(ii) Longest wavelength of Lyman series:
= R H [
−
] = R H [
]
Shortest wavelength of Balmer series:
= R H [
−
] = R H [
]
Now,
=
=
Lyman Series: When electrons will jump from higher energy orbit to
Balmer Series: When electrons will jump from higher energy orbit to
(ii) Longest wavelength of Lyman series:
Shortest wavelength of Balmer series:
Now,
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