CBSE Class 12 Physics 2022 Term 2 Outside Delhi Set 1 Solved Paper

Question : 10

Total: 12

In a Young's double slit experiment using light of wavelength 600nm, the slit separation is 0.8mm and the screen is kept 1.6m from the plane of the slits.
Calculate
(i) the fringe width
(ii) the distance of (a) third minimum and (b) fifth maximum, from the central maximum.3

Solution:

(i) Fringe width =β=

λD

∴β=

600×10−9×1.6

0.8×10−3

=12×10−4m
(ii) (a) Distance of 3rd minimum from central maximum =

β=30×10−4m
(b) Distance of 5th maximum from central fringe =5β=60×10−4m

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