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Question : 5
Total: 5
(a) The energy of hydrogen atom in an orbit is − 1.51 eV . What are kinetic and potential energies of the electron in this orbit?
(b) The electron in a hydrogen atom is typically found at a distance of about5.3 × 10 − 11 m from the nucleus which has a diameter of about 1.0 × 10 − 15 m . Assuming the hydrogen atom to be a sphere of radius 5.3 × 10 − 11 m , what fraction of its volume is occupied by the nucleus?
(b) The electron in a hydrogen atom is typically found at a distance of about
Solution:
(a) Total energy = − 1.51 e V
So, Potential energy= 2 × Total energy
= − 3.02 e V
Kinetic energy= − Total energy
= 1.51 e V
(b) Volume of nucleus=
π R 3
Volume of atom=
π R 3
Fraction of volume occupied by the nucleus=
=
= 8.39 = 8.4 × 10 − 16
So, Potential energy
Kinetic energy
(b) Volume of nucleus
Volume of atom
Fraction of volume occupied by the nucleus
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