CBSE Class 12 Physics 2023 Delhi Set 1 Paper

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Question : 25
Total: 35
Two coils C1 and C2 are placed close to each other. The magnetic flux ϕ2 linked with the coil C2 varies with the current I1 flowing in coil C1, as shown in the figure. Find

(i) the mutual inductance of the arrangement, and
(ii) the rate of change of current (
dI1
dt
)
that will induce an emf of 100V in coil C2.
(i) Since, N2ϕ2=MI1
From graph, ϕ2=10Wb corresponding to I1=4A
and ϕ2=10Wb
N2×10=M×4
Considering N2=1
M=
10
4
=2.5H

(ii) Again, N2ϕ2=MI1
Or,
d
dt
(N2ϕ2)
=
d
dt
(MI1)

Or, N2
dϕ2
dt
=M
dI1
dt

Considering N2=1
ε=M
dI1
dt

or, 100=2.5×
dI1
dt

dI1
dt
=40A s

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