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Question : 13
Total: 35
In an extrinsic semiconductor, the number density of holes is 4 × 10 20 m − 3 1.2 × 10 15 m 3
Solution: 👈: Video Solution
From law of mass action,
n i 2 = n e × n h
or,( 1.2 × 10 15 ) 2 = n e × 4 × 10 20
or,n e = ( 0.3 × 1.2 ) × 10 10
∴n e = 3.6 × 10 9 m − 3
or,
or,
∴
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