CBSE Class 12 Physics 2023 Outside Delhi Set 1 Paper

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Question : 21
Total: 35
In the given figure the radius of curvature of curved face in the plano-convex and the plano-concave lens is 15‌cm each. The refractive index of the material of the lenses is 1.5. Find the final position of the image formed.
Focal length of plano-convex lens be f1
‌
1
f1
‌
=(1.5−1)(‌
1
15
−‌
1
∞
)

Or,‌
1
f1
‌
=‌
1
30

∴ f1‌=30‌cm
Focal length of plano-concave lens be f2
‌
1
f2
‌
=(1.5−1)(‌
1
∞
−‌
1
15
)

∴‌‌f2‌=−30‌cm
since, parallel rays are incident on the plano convex lens it will form an image at a distance 30‌cm from the lens (since, focal length is 30‌cm ).
This image will act as an object for the plano concave lens.
Object distance =30−20=10‌cm
Applying lens formula,
‌
1
v2
−‌
1
u2
‌
=‌
1
f2

‌ Or, ‌‌‌‌
1
v2
−‌
1
10
‌
=−‌
1
30

So, v2=15‌cm
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