CBSE Class 12 Physics 2023 Outside Delhi Set 2 Paper

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Question : 4
Total: 13
A steady current of 8‌mA flows through a wire. The number of electrons passing through a cross-section of the wire in 10 s is
‌‌n=‌
It
e

‌ Or, ‌‌n=‌
8×10−3×10
1.6×10−19

∴‌n=5×1017
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