CBSE Class 12 Physics 2023 Outside Delhi Set 3 Paper

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Question : 11
Total: 13
SECTION - C

A ray of light is refracted by a glass prism. Obtain an expression for the refractive index of the glass in terms of the angle of prism A and the angle of minimum deviation 8m.
A ray is refracted by a glass prism.

Angle of deviation =δ=i1+i2+A
Angle of prism =A=r1+r2
For minimum deviation,
i1=i2 and r1=r2
δmin=2i1A
i1=
A+δm
2

Also, A=2r1
r1=
A
2

Refractive index =µ
=
sini1
sinr1
=
sin
A+δm
2
sin
A
2
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