CBSE Class 12 Physics 2023 Outside Delhi Set 3 Paper

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Question : 13
Total: 13
A resistor of 50, a capacitor of (
25
π
)
µ
F
and an inductor of (
4
π
)
H
are connected in series across an ac source whose voltage (in volt) is given by V=70 sin(100πt). Calculate:
(a) the net reactance of the circuit.
(b) the impedance of the circuit
(c) the effective value of current in the circuit.
(a) The net reactance =XLXC
=ωL
1
ωc

=100π×
4
π
1
100π×
25
π
×106

=400
106
2500
=400400

=0
(b) The impedance of the Circuit
Z=R2+(XLXC)2
=502+0
=50
(c) Peak current in the circuit =
70
50
A

So, the effective value of current is
Ieff =
70
50
×
1
2
=
7
52
A
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