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Question : 13
Total: 13
A resistor of 50 Ω , a capacitor of (
) µ F and an inductor of (
) H are connected in series across an ac source whose voltage (in volt) is given by V = 70 s i n ( 100 π t ) . Calculate:
(a) the net reactance of the circuit.
(b) the impedance of the circuit
(c) the effective value of current in the circuit.
(a) the net reactance of the circuit.
(b) the impedance of the circuit
(c) the effective value of current in the circuit.
Solution: 👈: Video Solution
(a) The net reactance = X L − X C
= ω L −
= 100 π ×
−
= 400 −
= 400 − 400
= 0
(b) The impedance of the Circuit
Z = √ R 2 + ( X L − X C ) 2
= √ 50 2 + 0
= 50 Ω
(c) Peak current in the circuit=
A
So, the effective value of current is
I eff =
×
=
A
(b) The impedance of the Circuit
(c) Peak current in the circuit
So, the effective value of current is
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