ICSE Class 10 Chemistry 2020 Solved Paper
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Question : 69
Total: 86
State the volume occupied by 40 gm
Solution:
Given : V.D. of Methane = 8
Molecular mass = V.D. × 2 = 8 × 2 = 16
If16 gm CH 4
= 22.4 l at STP
Then40 gm CH 4
=
× 40
= 56 l
If
Then
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