The percentage of phosphorus in the fertilizer super phosphate Ca ( H 2 PO 4 ) 2 correct to 1 decimal point. [At. Wt. H = 1 , P = 31 , O = 16 , C a = 40 ]

ICSE Class 10 Chemistry 2023 Solved Paper

Calculate:

Question : 74

Total: 88

The percentage of phosphorus in the fertilizer super phosphate Ca(H2PO4)2 correct to 1 decimal point. [At. Wt. H=1 , P=31,O=16,Ca=40]

Solution:

Molecular mass of Ca(H2PO4)2
‌=40+(1×2+31+16×4)×2
‌=234‌amu.
Percentage of Phosphorous
‌=‌

‌ Mass of phosphorous in one molecule ‌

‌ Molecular mass of compound ‌

‌=‌

234

×100=26.49%

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