ICSE Class 10 Physics 2015 Solved Paper

A cell of Emf 2V and internal resistance 1.2Ω is connected with an ammeter of resistance 0.8Ω and two resistors of 4.5Ω and 9Ω as shown in the diagram below :

Question : 60

Total: 74

What is the potential difference across the terminals of the cell?

Solution:

‌‌ Terminal Voltage (V) ‌
=E−Ir=2−0.4×1.2
‌=2−0.48
‌=1.52‌ volt.

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