ICSE Class 10 Physics 2016 Solved Paper

Question : 6

Total: 73

Calculate the mass of ice required to lower the temperature of 300g of water at 40∘C to water at 0∘C.
(Specific latent heat of ice =336J∕g,
Specific heat capacity of water =4.2J∕g∘C ).

Solution:

Heat extracted by ice at 0∘C to melt = Heat given by water to reach 0∘C from 40∘C.
ML=mcθ
Where, θ= change in temperature of water
L= Specific Latent heat of ice
c= Specific heat capacity of water
M= Mass of ice required
m= mass of water
Heat gained by ice = Heat lost by water
M×336‌=300×4.2×(40−0)
M‌=‌

300×4.2×40

336

=150‌gm
∴ Ice is required to lower the temperature of water =150‌gm.

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