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ICSE Class 10 Physics 2016 Solved Paper

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A battery of emf 12V and internal resistance 2Ω is connected with two resistors A and B of resistance 4Ω and 6Ω respectively joined in series.

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Question : 63
Total: 73
The potential difference across 6Ω Resistor.
Solution:  
Potential difference across 6Ω=IR
=1×6=6V
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