ICSE Class 10 Physics 2016 Solved Paper
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A battery of emf 12 V and internal resistance 2 Ω is connected with two resistors A and B of resistance 4 Ω and 6 Ω respectively joined in series.
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Question : 63
Total: 73
The potential difference across 6 Ω Resistor.
Solution:
Potential difference across 6 Ω = IR
= 1 × 6 = 6 V
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