ICSE Class 10 Physics 2016 Solved Paper

A battery of emf 12V and internal resistance 2Ω is connected with two resistors A and B of resistance 4Ω and 6Ω respectively joined in series.

Find:

Question : 62

Total: 73

The terminal voltage of the cell.

Solution:

‌‌ Voltage drop Ir ‌=1×2=2‌ volt ‌
‌ Terminal Voltage ‌‌=‌ emf ‌−‌ Voltage drop ‌
‌=12−2=10‌ volts. ‌

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