ICSE Class 10 Physics 2017 Solved Paper

Question : 8

Total: 65

A solid of mass 50g at 150∘C is placed in 100 g of water at 11∘C , when the final temperature recorded is 20∘C . Find the specific heat capacity of the solid.
(Specific heat capacity of water =4.2j∕g∘C )

Solution:

Given : Mass of solid (m1)=50g
Initial temperature of solid =150∘C
Mass of water (m2)=100g
Intial temperature of mixture =11∘C
Final temperature of mixture =20∘C
Specific heat capacity of water (c2)=4.2J∕g∘C
By the principle of calorimetry,
Heat lost by hot body = Heat gained by cold body.
⇒‌m1c1∆T1‌=m2c2∆T2
⇒50×c1×(150−20)‌=100×4.2(20−11)
⇒50×c1×130‌=100×4.2×9
⇒‌c1‌=‌

100×4.2×9

50×30

‌=‌0.58Jg−1‌∘C−1

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