ICSE Class 10 Physics 2018 Solved Paper
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A half metre rod is pivoted at the centre with two weights of 20 gf and 12 gf suspended at a perpendicular distance of 6 cm and 10 cm from the pivot respectively as shown below.
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Question : 41
Total: 78
Is the rod in equilibrium?
Solution:
Clockwise moment of force
= 12 gf × 10 cm
= 120 gf − cm
Anticlockwise moment of force
= 20 gf × 6 cm
= 120 gf − cm
since, the clockwise moment of force is equal to the anticlockwise moment of force, the rod is in equilibrium
Thus, Yes, the rod is in equilibrium.
Anticlockwise moment of force
since, the clockwise moment of force is equal to the anticlockwise moment of force, the rod is in equilibrium
Thus, Yes, the rod is in equilibrium.
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