ICSE Class 10 Physics 2018 Solved Paper
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An electric iron is rated 220 V , 2 k W
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Question : 61
Total: 78
If the iron is used for 2 h ₹ 4.25 per kWh
Solution:
Given: P = 2 kW
Time( t ) = 2 h
Energy consumed in 1 day
= Power × time
= 2 kW × 2 h
= 4 kW h
∴
= 4 kWh × 7
= 28 kW h .
∴
= ₹ 4.25 × 28
= ₹ 119
Time
Energy consumed in 1 day
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