ICSE Class 10 Physics 2020 Solved Paper

SECTION - II

The figure below shows a simple pendulum of mass 200g. It is displaced from the mean position A to the extreme position B. The potential energy at the position A is zero. At the position B the pendulum bob is raised by 5m.

Question : 29

Total: 67

What is the speed of the bob at the position A when released from B ?
(Take g=10ms−2 and there is no loss of energy.)

Solution:

Let the speed of the bob at position A be ' v '.
Total mechanical energy at A = Total mechanical energy at B
‌

mv2+0‌=10
‌

×‌

200

1000

×v2‌=10
v2‌=‌

2000×10

200

v2=100,∵v=√100=10m∕ s

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