ICSE Class 10 Physics 2023 Solved Paper

A metre scale of weight 50‌gf can be balanced at 40‌cm mark without any weight suspended on it.

Question : 52

Total: 76

What minimum weight placed on this metre ruler can balance this ruler when it is pivoted at its centre?

Solution:

To balance the ruler with minimum weight of ' W ' gf, the weight must be suspended from 100‌cm mark.
In equilibrium,
Sum of anticlockwise moment = sum of clockwise moment.
‌⇒50×10‌gf‌cm=W×50‌gf‌cm
‌∴‌‌W=‌

500

=10‌gf

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