ICSE Class 10 Physics 2023 Solved Paper
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Question : 70
Total: 76
Calculate the total amount of heat energy required to melt 200 g 0 ∘ C 100 ∘ C
(Specific latent heat of ice= 336 Jg − 1 = 4.2 Jg − 1 ∘ C − 1 )
(Specific latent heat of ice
Solution:
Ice at 0 ∘ C
0 ∘ C
water [ at 100 ∘ C ]
Givenm = 200 g , L ice = 336 Jg − 1
C water = 4.2 Jg − 1 ∘ C − 1
Q 1 = m L
= 200 × 336
= 67 , 200 J
Q 2 = m c ∆ T
= 200 × 4.2 × ( 100 − 0 )
= 84000 J
Total amount of heat = Q 1 + Q 2
= 67200 + 84000
= 1 , 5 1 , 2 0 0 J
Given
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