ICSE Class X Math 2014 Solved Paper

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Question : 37
Total: 52
Let A=[
21
02
]
,B=[
41
32
]
and C=[
32
14
]
Find A2+AC5B.
Solution:  
Given:
A=[
21
02
]
,B=[
41
32
]
,
C=[
32
14
]

A2=AA=[
21
02
]
[
21
02
]

=[
4+022
0+00+4
]

=[
40
04
]

AC=[
21
02
]
[
32
14
]

=[
614+4
0+208
]
=[
78
28
]

and 5B=5[
41
32
]

=[
205
1510
]

Now,
A2+AC5B=[
40
04
]
+[
78
28
]
[
205
1510
]

=[
47200+85
0+2+1548+10
]

=[
233
176
]
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